1.Problem / Purpose
The purpose of this experiment is to investigate the properties of an enzyme - substrate reaction
2.Hypothesis
Hydrogen peroxide is a very reactive compound that can be used for a variety of reactions including bleaching and disinfecting minor wounds. Acting as an oxidizing agent, it is also toxic to cells, hence its value as a disinfecting agent that disrupts the metabolism of bacteria. Our body cells and those of many other animals contain an enzyme called catalase that accelerates the conversion of toxic hydrogen peroxide to water and oxygen gas.
In this experiment, if the concentration of the enzyme is increased, then the reaction will proceed faster and if the concentration of the enzyme will decrease, then the reaction will proceed slower.
3.Materials
All the materials used in the experiment are presented on the lab sheet
4.Procedure
The instructions for the experiment are presented on the lab sheet
5.Observations
TRIAL
#ENZYME CONCENTRATION
[cc]AMOUNT OF mL OF GAS EVOLVED AT THE END OF ...TOTAL EVOLVED
[mL]
10 s20 s30 s40 s50 s60 s90 s120 s
11.001524364045516579250
0.50510162127314563245
0.2538121922263242239
0.121246781114237
21.001224334244506478248
0.5049152026304462240
0.2547111620243243244
0.122347891115248
31.001422354245516579252
0.5039162025294360248
0.2538141925273345240
0.121358991015245
41.001523323843486277243
0.50611172228324562248
0.2549121722263343245
0.121247791218245
6.Analysis Questions
6.1.Question #1:
SUBSTRATE: Hydrogen Peroxide (H2O2 (l))
PRODUCTS: Water (H2O(l)) and Oxygen gas (O2 (g))
6.2.Question #2:
From theory, at STP, 1 mol of a gas is equal to 22400 mL or 22400 g
( ) = m (1.2)
where: ÃÂî The number of moles of Hydrogen Peroxide: = ;
ÃÂî The molar mass of Hydrogen Peroxide: = ;
ÃÂî The mass of Hydrogen Peroxide: m ;
2 mol = 64.08 g
( ) = m (1.3)
where: ÃÂî The number of moles of Oxygen gas: = ;
ÃÂî The mass of a gas at STP:...