Metric Lab #2 Data, Results, Calculations Mass Measure 1. The mass of the largest test tube was 32.08g.
(32.08g) x (1000mg) = 32 080mg.
1 1g We got this information by weighing the test tube upside-down on the scale and recording the mass to the nearest hundredth of a gram. Then, using System Analysis, we converted grams to milligrams.
Length Measure 2. The length of the largest test tube was 15 cm.
(15cm) x (10mm) = 150mm 1 1cm We got out information using a metric ruler and rounding the results in centimeters. Then, we measured and recorded it in millimeters.
Area Determination 3. The area of the filter paper was 128.7 g/cm3.
Use formula"ÃÂ¦pr2 Diameter of the circle was 12.8 cm. I then divided that by 2 to get the radius (r).
p (6.4)2= 128.7 cm2.
First we measured the diameter and divided it into two. Then by fitting the data in the formula, we were able to come up with the area of the round filter paper.
Volume Measurement 4. The volume of the largest test tube was 59.7 ml.
(59.7ml) x ( 1L. ) = .0597 L.
We got the volume of the graduated cylinder by filling it up to the top with water and pouring all of it into a measuring tube and reading from the line where the water reaches. We used System Analysis to convert milliliters to liters.
Density Determination 5. The density of ethyl alcohol is .778 g/cm3.
Density = Mass Volume Mass = 47.84g. (Alcohol + Tube) "" 40.58g. (Test Tube Alone) = 6.99 Volume = 9 ml. Of ethyl alcohol.
Density = 6.99g = .778g/ml3.
First, we had to weigh the tube by itself, which was subtracted by the mass of the tube and the alcohol to find the mass of the alcohol. Then, I divided that by the amount of alcohol to find the density of ethyl alcohol, which is less dense than water.
6. The density of rock # 14 was 3.104 g/cm3.
Density = Mass Volume Mass = 22.94g (rock) Volume = 69 ml. (Water + Rock) "" 60 ml. (Water alone) = 9 ml.
Density = 22.94g = 3.104 g/ml 3.
I used the same process to find density as I did in #5. Except, instead of having to find the different in Mass, I had to find the difference in Volume.
Questions: 1. Area of paper = Length x Width Area= 8.5in. x 11in. = 93.5 in2.
2. How many seconds are in a day? 1 Day = (24 hr) x (60 min) x (60 sec) = 86 400 s/day.
1 day 1 hr 1 min 3. Convert the following showing unit analysis: a. 35.5 km = m 35.5 km = 1000 m = 35 000 m 1 km Answer: 35 000 m b. 125 mm = cm 125 mm = 1 cm = 12.5 cm 10mm Answer: 12.5 cm c. 8.66 kg = mg 8.66 kg = 1000 g x 1000mg = 8 660 000 mg 1 kg 1 g Answer: 8 660 000 mg d. 2.50 nm = m 2.50 nm = 1 000 000 000 m = 2 500 000 000 m 1 nm Answer: 2 500 000 000 m e. 45.0 s = h 45.0 s = 1 min x 1 hr = .013 hr 60 sec 60 min Answer: .013 hr f. 9.9 mL = L 9.9 mL = 1L . = .01 L 1000 mL Answer: .01 L Question #4 To use Unit Analysis, you multiply of divide to the right the closest converting scale to the unit you are trying to reduce or make larger. You are converting using a method that you can show your work and find where you made your mistake easily.