# Investigation of free fall.

Essay by rocky_kal_elCollege, UndergraduateA+, May 2007

download word file, 3 pages 3.1 1 reviews

Downloaded 35 times

Presentation & Analysis Of Results Ascertained: Table 1 ~ The table depicts the results obtained and manipulated to calculate mathematically the uncertainties of displacement, time and the total percentagerelative error. No. Of Blocks Time (s) Average Time (s) Uncertainty For Time (s) Percentage Relative Error (%) 10 0.71 0.61 0.69 2.01 / 3 = 0.67 + 0.03 + 4.47 15 0.78 0.71 0.83 2.32 / 3 = 0.77 + 0.03 + 3.89 20 0.83 0.94 0.90 2.67 / 3 = 0.89 + 0.03 + 3.37 25 1.04 1.05 1.07 3.16 / 3 = 1.05 + 0.03 + 2.85 30 1.15 1.07 1.10 3.32 / 3 = 1.11 + 0.03 + 2.70 35 1.08 1.22 1.21 3.51 / 3 = 1.17 + 0.03 + 2.56 40 1.44 1.41 1.29 4.14 / 3 = 1.38 + 0.03 + 2.17 Time Squared (s2Ã¯Â¿Â½) 0.45 0.59 0.79 1.10 1.23 1.37 1.90 Presentation & Analysis Of Results Ascertained: Table 2 ~ The table depicts the Uncertainties and Percent Relative Error for Time Squared (s2) Derivation Of The Gradient Of The Graph Of Time Against Displacement Derivation One (1): ÃÂd d1 - d0 30.0

- 0 30.0 + 0.10 V1 = = = = = 28.3 cm s-1 + 0.13 ÃÂ t t1 - t0 1.06 - 0 1.06 + 0.03 Derivation Two (2): ÃÂd d2 - d1 60.0 - 30.0 30.0 + 0.20 V2 = = = = = 37.5 cm s-1 + 0.26 ÃÂ t t2 - t1 1.86 - 1.06 0.80 + 0.06 Derivation Three (3): ÃÂd d3 - d2 90.0 - 60.0 30.0 + 0.20 V2 = = = = = 88.2 cm s-1 + 0.26 ÃÂ t t3 - t2 2.20 - 1.86 0.34 + 0.06 Derivation Four (4): ÃÂd d4 - d3 120.0 - 90.0 30.0 + 0.20 V2 =...